Study the circuit shown in which three identical bulbs `B_(1) B_(2)` and `B_(3)` are connected in parallel with a battery of 4.5 V
(i) What will happen to the glow of other two bulbs if the bulb `B_(3)` gets fused ?
(ii) If the wattage of each bulb is 1.5 W, how much reading will the ammeter A show when all the three bulbs glow simultaneously.
(iii) Find the total resistance of the circuit.

Explanation

(i) Other bulbs will glow with same brightness.
(ii) When the bulbs are in parallel, wattage will be added (4.5 W) and the ammeter reading would be
`becauseI=(P)/(V) = (4.5 W)/(4.5V)= 1.0 ` Ampere
(iii) Since ammeter reading is 1.0 ampere resistance of the combination is `(4.5V)/(1.0A)= 4.5 Omega`