How many resistors of 88 `Omega` are connected in parallel to carry 10 A current on a 220 V line ?

Explanation

Let n number of resistances are connected in parallel.
Equivalent resistance `, (1)/(R_(P)) = (n)/(88)`
`R_(p) = (88)/(n)`
V = IR or R` = (V)/(I)`
`(88)/(n) = (220)/(10)`
`n = (88) /(22)` = 4 resistors