Find out the following in the electric circuit given in the figure.
(i) Effective resistance of two 8` Omega` resistors In the combination
(ii) Current flowing through 4` Omega` resistor
(iii) Potential difference across 4`Omega` resistor
(iv) Power dissipated in 4`Omega` resistor
(v) Difference in reading of ammeter `A_(1)` and `A_(2)` ( if any) .

Explanation

(i) Effective resistance of two `8Omega` resistors
`(1)/(R)=(1)/(8) +(1)/(8)=(2)/(8)`
`R=4 Omega`
(ii) Current flowing through the circuit = current flowing though `4Omega`
Equivalent resistance of the circuit =` 4 Omega+ 4 Omega`
`= 8 Omega`
Current flowing in the circuit `= (V)/(R) = (8V)/(8 Omega)= 1 A `
(iii) Potential difference across `4Omega = V_(1) = IR_(1)`
`= 1A xx4 Omega= 4V `
(iv) Power dissipated in `4 Omega= P = VI = 4 V xx1 A `
= 4 watt
(v) Both `A_(1)` and `A_(2)` show same reading because current remains same in series combination.