Redraw the circuit of question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure potential difference across the 12 `Omega` resistor. What would be the readings in the ammeter and the voltmeter?

Explanation

`R_(s) =(5+8+12)`
`=25 Omega`
V= IR
`I = (V)/(R) = (6)/(25) = 0.24 A `
Potential difference across `12 Omega` resistor is
`V = IR = 0.24xx12= 2.88` V
Hence reading of ammeter `= 0.24 A` reading of voltmeter = 2.88 V