How many `176Omega` resistors (in parallel) are required to carry 5A on a 220 V line ?

Explanation

I = 5A
V = 220 V
`Rp= (V)/(I) = (220)/(5) = 44 Omega`
Now, if n resistors, each o.f resistance 176 `Omega` are connected in parallel to give equivalent resistance of 44`Omega`, i.e. `R_(p)`
`R_(p)= (R)/(n)`
`44=(176)/(n)`
`n=(176)/(44) = 4`