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An element is placed in 2nd group and 3r...

An element is placed in 2nd group and 3rd period of the periodic table, burn in presence of oxygen to form a basic oxide :
(i) Identify the element
(ii) Write the electronic configuration
(iii) Write the balanced equation when it burns in the presence of air.
(iv) Write a balanced equation when this oxide is dissolved in water.
(v) Draw the electron dot structure for the formation of this oxide.

Text Solution

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(i) Magnesium.
(ii) Electronic configuration is 2,8, 2
(iii) `2Mg+O_(2)to2MgO`
(iv) `MgO+H_(2)OtoMg(OH)_(2)`
(v) `Mg toMg^(2+)+2e^(-)`
2,8,2 2, 8
`O+2e^(-)toO^(-2)`
2,6 2,8
is electron dot structure.
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