The time period of a thin bar magnet in earth's magnetic field is T. If the magnet is cut into two equal parts perpendicular to its lengh, the time period of each part in the same field will be

The time period of a bar magnet in uniform magnetic field vec(B) is 'T'. It is cut into two halves, by cutting it parallel to its length then the time period of each part in same field is

The period of a thin magnet in a magnetic field is 2s . It is cut into four equal parts by cutting it along length and breadth. The period of each of them in the same field is

The time period of a bar magnet oscillating in a uniform magnetic field is 3 seconds. if the magnet is cut into two equal parts along the equatorial line of the magnet and one part is made to vibrate in the same field, what is the time period ?

The period of oscillation of a freely suspended bar magnet is 4 second. If it is cut into two equal parts length wise then the time period of each part will be

A thin magnetic needle oscillates in the horizontal plane with a time period of 2.0 sec. If the needle is broken into 4 equal parts perpendicular to its length, then the time period of each part will be:

The time period of a freely suspended bar magnet in a field is 2s. It is cut into two equal parts along its axis, then the time period is

The time period of a freely suspended bar magnet in a field is 2s. It is cut into two equal parts along its axis, then the time period is