[H sum_(1)^(18)(x_(j)-7)=9" and "sum_(1)^(18)(x_(1)-7)^(2)=45," then the slandard devialian about the mean is "],[2.25],[1.5],[3],[" Nong of these "]

If sum_(i=1)^(18)(x_(i)-8)=9 and sum_(i=1)^(18)(x_(i)-8)^(2)=45 then the standard deviation of x_(1),x_(2),...,x_(18) is

If sum_(i=1)^(18)(x_(i)-8)=9 and sum_(i=1)^(18)(x_(i)-8)^(2)=45 then find the standard deviation of x_1 , x_2, ....,x_(18)

If sum_(i=1)^(5) (x_(i) - 6) = 5 and sum_(i=1)^(5)(x_(i)-6)^(2) = 25 , then the standard deviation of observations

If sum_(i=1)^(5) (x_(i) - 6) = 5 and sum_(i=1)^(5)(x_(i)-6)^(2) = 25 , then the standard deviation of observations

If x_(1), x_(2), "…......." x_(18) are observation such that sum_(j=1)^(18)(x_(j) -8) = 9 and sum_(j=1)^(18)(x_(j) -8)^(2) = 45 , then the standard deviation of these observations is

If x_(1), x_(2), "…......." x_(18) are observation such that sum_(j=1)^(18)(x_(j) -8) = 9 and sum_(j=1)^(18)(x_(j) -8)^(2) = 45 , then the standard deviation of these observations is

If sum_(i=1)^(9) (x_(i)-5)=9 " and" sum_(i=1)^(9) (x_(i)-5)^(2)=45 , then the standard deviation of the 9 items x_(1),x_(2),..,x_(9) is

If sum_(i=1)^(9)(x_(i)-5)=9 and sum_(i=1)^(9)(x_(i)-5)^(2)=45 then the standard deviation of the 9 items x_(1),x_(2),......,x_(9) is

If sum_(i=1)^(9) (x_(i)-5) " and" sum__(i=1)^(9) (x_(i)-5)^(2)=45 , then the standard deviation of the 9 items x_(1),x_(2),..,x_(9) is