" The radius of the circle "r=sqrt(3)sin theta+cos theta" is "

The radius of the circle r = 12 cos theta + 5 sin theta is

The radius of the circle r^(2)-2sqrt(2r) (cos theta + sin theta)-5=0 , is

The radius of the circle r^(2)-2sqrt(2r) (cos theta + sin theta)-5=0 , is

The value of theta for which sqrt3 cos theta-sin theta=1 is :

z=i+sqrt(3)=r(cos theta+sin theta)

cos theta+sqrt(3)sin theta=2

Express (cos theta - sin theta)" in the form " r cos (theta+ alpha) and (sqrt 3sin theta + cos theta) " in the form r" sin(theta + beta).