Complete combustion of `0.858 g` of compound `X` given `2.64g` of `CO_2 and `1.26gg` of `H_2O.` The lowest molecular mass `X` can have:

Complete combustion of 0.858 g of compound X given 2.64g of CO_2 and 1.26 g of H_(2)O. The lowest molecular mass X can have:

Complete combustion of 0.858 g of compound X given 2.64g of CO_2 and 1.26g of H_2O The lowest molecular mass X can have ;

Complete combustion of 0.858 g of compound X gives 2.63 g of CO_(2) and 1.28 g of H_(2) O. The lowest molecular mass X can have

Complete combustion of 0.858 g of compound X gives 2.63 g of CO_(2) and 1.28 g of H_(2) O. The lowest molecular mass X can have

Complete combustion of 1.18 g of organic compound gives 2.64 g of CO_(2) & 1.26 g " of " H_(2)O . Find emprical formula of compound ?

Complete combustion of a sample of hydrocarbon Q gives 0.66 g of CO_2 and 0.36 g of H_2O .The emptical formula of the compound is

Complete combustion of 1.80g of an oxygen containing compound " (C_(x)H_(y)O_(z)) gave 2.64g of CO_(2) and 1.08g of H_(2)O .The percentage of oxygen in the organic compound is:

44g of a sample on complete combustion given 88g CO_2 and 36g of H_2 O. The molecular formula of the compound may be :

44g of a sample on complete combustion given 88g CO_2 and 36g of H_2 O. The molecular formula of the compound may be :