The temperature of ice is `– 10°C` [specific heat = `0.5 kcal//(kg-°C)`] and that of water `60°C`. They are mixed in equal amounts. What part of the ice will be melted ?

150 g of ice is mixed with 100 g of water at temperature 80^(@)C . The latent heat of ice is 80 cal/g and the specific heat of water is 1 cal//g-.^(@)C . Assuming no heat loss to the environment, the amount of ice which does not melt is –

Water of mass m_(2) = 1 kg is contained in a copper calorimeter of mass m_(1) = 1 kg . Their common temperature t = 10^(@)C . Now a piece of ice of mass m_(2) = 2 kg and temperature is -11^(@)C dropped into the calorimeter. Neglecting any heat loss, the final temperature of system is. [specific heat of copper =0.1 Kcal//kg^(@)C , specific heat of water = 1 Kcal//kg^(@)C , specific heat of ice = 0.5 Kcal//kg^(@)C , latent heat of fusion of ice = 78.7 Kcal//kg ]

Water of mass m_(2) = 1 kg is contained in a copper calorimeter of mass m_(1) = 1 kg . Their common temperature t = 10^(@)C . Now a piece of ice of mass m_(2) = 2 kg and temperature is -11^(@)C dropped into the calorimeter. Neglecting any heat loss, the final temperature of system is. [specific heat of copper =0.1 Kcal//kg^(@)C , specific heat of water = 1 Kcal//kg^(@)C , specific heat of ice = 0.5 Kcal//kg^(@)C , latent heat of fusion of ice = 78.7 Kcal//kg ]

Ice in a freezer is at –7^(@)C . 100 g of this ice is mixed with 200 g of water at 15°C. Take the freezing temperature of water to be 0°C, the specific heat of ice equal to 2.2 J//g .^(@)C , specific heat of water equal to 4.2 J//g .^(@)C , and the latent heat of ice equal to 335 J/g. Assuming no loss of heat to the environment, the mass of ice in the final mixture is closest to

5 gm of ice at -10^@C are mixed with 20 gm of water at 39^@C . Will whole of the ice melt? If so, what is the final temperature of the mixture? Specific heat capacity of ice = 0.5 cal gm^-1 "^@C^-1 and latent heat of fusion of ice = 80 cal gm^-1 , specific heat capacity of water = 1cal gm^-1 "^@C^-1 .

10gm ice at -10^(@)C is put in 30gm water at 30^(@)C . Final temperature of mixture (in^(@)C) is : Given (specific heat capacity of ice & water are 0.5 cal / gm^(@)C respectively and Latent heat of ice = 80 cal/gm).Write your answer in nearest integer.