Calculate the extent of hydrolysis of 0.005 M `K_2CrO_4. [K_2= 3.1 xx 10^(-7)" for "H_2CrO_4]` (It is essentially strong for first ionization)

Calculate the percent degree of hydrolysis of 0.005 M K_(2)CrO_(4).K_(a_(2))=5xx10^(-7) for H_(2)CrO_(4) .(it is essentially strong for first ionization)

Calculate the extent of hydrolysis and the pH of 0.1 M ammonium acetate Given that K_a=K_b=1.8xx10^(-3) .

Solubility of Ag_(2)CrO_(4) ( K_(sp)=4xx10^(-13) ) in 0.1 M K_(2)CrO_(4) solution will be :

Calculate the solubility of Ag_(2)CrO_(4) in 0.1M AgNO_(3)K_(sp) of Ag_(3)CrO_(4)=1xx10^(-22)

The degree of hydrolysis of 0.005 M aqueous solution of NaOCN will be ( K_a for HOCN = 4.0xx10^-4 )

The degree of hydrolysis of 0.005 M aqueous solution of NaOCN will be ( K_a for HOCN = 4.0xx10^-4 )