If the function `f: R to R ` defined by `f(x)=(3^(x)+3^(-x))/(2)`, then S.T `f(x+y)+f(x-y)=2f(x)f(y)`.

If the function f:R rarr R defined by f(x)=(3^(x)+3^(-x)) , then show that f(x+y) = f(x-y) = 2f(x)f(y) .

" If the function "f:R rarr R" defined by "f(x)=(3^(x)+3^(-x))/(2)," then show that "f(x+y)+f(x-y)=2f(x)f(y)"

If f: R - {0} to R is defined by f(x) = x^(3)-1/(x^3) , then S.T f(x) + f(1//x) = 0 .

A function f : R rarr defined by f(x) = x^(2) . Determine {y : f(y) = - 1}

A function f : R -> R^+ satisfies f(x+y)= f(x) f(y) AA x in R If f'(0)=2 then f'(x)=

If for a function f : R to R f (x +y ) =F(x ) + f(y) for all x and y then f(0) is

If f(x) is a real valued and differentaible function on R and f(x+y)=(f(x)+f(y))/(1-f(x)f(y)) , then show that f'(x)=f'(0)[1+t^(2)(x)].

A function f:R rarr R is defined by f(x+y)-kxy=f(x)+2y^2, AA xy in R and f(1)=2, f(2)=8 , where k is some constant, then f(x+y). (1/(x+y)) is equal to (where x+y ne y)