`(1-costheta+isintheta)/(1+costheta-isintheta)`

if |(2iz_1-z_1-z_2)/(2iz_1-z_1-z_2)|=|(costheta+ isintheta)/(costheta-isintheta)| then prove that z_1/z_2 is purely real.

Select and write the correct answer from the given alternatives in each of the following: Let z = (costheta + isintheta) / (costheta - isintheta) , pi / 4 < theta < pi / 2 . Then, arg z is

Assertion (A) : (Costheta+iSintheta)^(10)+(Costheta-iSintheta)^(10)=2cos10theta Reason (R) : (1+costheta+isintheta)^n+(1+costheta-isintheta)^n= 2^(n+1)cos^n(theta/2)cos((ntheta)/(2))

(costheta+isintheta)^(10)+(costheta-isintheta)^(10)

(1-costheta+isintheta)^8 =

(1-costheta+isintheta)^(6)

(1-costheta+isintheta)^6 =

Let z=(costheta+isintheta)/(costheta-isintheta), pi/4 lt theta lt pi/2 . Then arg(z) =

If (1+costheta+isintheta)(1+cos2theta+isin2theta)=x+iy then y =

If (1+costheta-isintheta)(1+cos2theta+isin2theta)=x+iy then x^2+y^2 =