int_(0)^(2)|x-1|dx=

int_(0)^(2)[x-1]dx= Where [x] denotes the

Evaluate the following integral: int_(0)^(1)|2x-1|dx

int_(0)^(1)|2x-1|dx=? (a) 2 (b) (1)/(2) (c) 1 (d) 0

Evaluate int_(0)^(2)||x-1|-x|dx

int_(0)^(2)|1-x|dx

Match the following : {:(" LIST - I","LIST - II"),("I)" int_(0)^(2)|1-x|dx=,"a) " 1),("II)" int_(0)^(2)|x-2|dx=,"b) "2),("III)" int_(0)^(2)(|x|+|x-1|)dx=,"c) "3):}

The value of int_(0)^(2)|1-x|dx

Evaluate: int_(0)^(2)|1-x|dx

Evaluate: int_(0)^(2)|1-x|dx