In a YDSE setup interference fringes are obtained by sodium light of wavelength `5890Å`. On screen the fringes have an angular width `0.20^(@)`. Now the wavelength of light is changed and it is found that fringe width increases by 10%, the new wavelength of incident light is :

The interference fringes for sodium light (lambda = 5890 Å) in a double slit experiment have an angular width of 0.2^(@) . For what wavelength will width be 10% greater.

If the wavelength of light is kept constant and the biprism is moved towards the screen, then the fringe width

In Young's double slit experiment, the fringe width with light of wavelength 6000 Ã… is 3 mm. The fringe width, when the wavelength of light is changed to 4000 Ã… is

In Young's double slit experiment, the fringe width with light of wavelength 6000 Ã… is 3 mm. The fringe width, when the wavelength of light is changed to 4000 Ã… is

In a Young's double-slit experiment the fringe width is 0.2mm . If the wavelength of light used is increased by 10% and the separation between the slits if also increased by 10%, the fringe width will be

In a Young's double-slit experiment the fringe width is 0.2mm . If the wavelength of light used is increased by 10% and the separation between the slits if also increased by 10%, the fringe width will be

In YDSE wavelength of light used is 500 nm and slit width is 0.05 mm . then the angular fringe width will be.

In YDSE wavelength of light used is 500 nm and slit width is 0.05 mm . then the angular fringe width will be.

In young's double slit experiment the slits are illumated by light of wavelength 5890^(@) A and the distance between the fringes obtained on the screen is 0.2^(@) . If the whole apparatus is immersed in water then the angular fringe width will be, if the refractive index of water is 4//3