50 ml of water sample requires 10 ml of `(M)/(50)HCl` for complete neutralization. Calculate hardness of `H_(2)O` (temporary) in ppm.

50 ml of water sample, containing temporary hardness only, required 0.1 ml of M/50 HCl for complete neutralisation. Calculate the temporary hardness of water in ppm.

100 mL of a sample of tap water requires 50 mL of N // 50- HCl solution for titration. Calculate the temporary hardness of tap water.

1 g of impure Na_(2)CO_(3) is dissolved in water and the solution is made upto 250 mL . To 50 mL of this solution, 50 mL of 0.1 N HCl is added and the mixture after shaking well required 10 mL of 0.16 N NaOH solution for complete neutralization. Calculation percent purity of the sample of Na_(2) CO_(3) .

1 g of impure Na_(2)CO_(3) is dissolved in water and the solution is made upto 250 mL . To 50 mL of this solution, 50 mL of 0.1 N HCl is added and the mixture after shaking well required 10 mL of 0.16 N NaOH solution for complete neutralization. Calculation percent purity of the sample of Na_(2) CO_(3) .

100 mL of a sample of hard water requires 25.1 mL of 0.02 N H_(2)SO_(4) for complete reaction, The hardness of water ( density 1g//mL) is:

100 mL of a sample of hard water requires 25.1 mL of 0.02 N H_(2)SO_(4) for complete reaction, The hardness of water ( density 1g//mL) is:

A 200 mL sample of water requires 5 " mL of " (N)/(20)Na_2CO_3 solution for complete precipitation of Ca^(2+) and CaCO_3 . Calculate the hardness in ppm.