In an astronomical telescope, focal length of objective lens is `75 cm` and that of eye piece is `5 cm` . Calculate the magnifying power and the distance between the two lenses, when final image of distant object is seen at a distance of `25 cm` from the eye.

In an astronomical telescope, the focal length of the objective lens is 100 cm and of eye-piece is 2 cm . The magnifying power of the telescope for the normal eye is

In an astronomical telescope, the focal length of the objective lens is 100 cm and of eye-piece is 2 cm . The magnifying power of the telescope for the normal eye is

In an astronomical telescope, the distance between the objective lens and eyepiece is 20 cm. In normal adjustment, the magnifying power of the telescope is 15. Find the focal length of the objectives lens.

In an astronomical telescope, the focal length of objective lens and eye-piece are 150 cm and 6 cm respectively. In case when final image is formed at least distance of distinct vision. the magnifying power is

A small telescope has an objective lens of focal length 144 cm and eye piece of focal length 6.0 cm. What is the magnifying power of the telescope ?

In an astronomical telescope, focal length of eye piece is 5 cm and focal length of objective is 75 cm . The final image is formed at the least distance of distinct vision (=25 cm) from the eye. What is the magnifying power of the telescope ?

The focal length of objective and eye-piece of astronomical telescope are 2 m and 5 cm respectively. The magnifying power of telescope when final image is formed at infinity is

The focal lengths of the objective and the eye piece of an astronomical telescope are 60 cm and 5 cm respectively. Calculate the magnifying power and the length of the telescope when the final image is formed at (i) infinity, (ii) least distance of distinct vision (25 cm)