[" If "p" be the length of the perpendicular from the "],[" origin to the line "(x)/(a)+(y)/(b)=1" then "],[square" A."(1)/(P^(2))=a^(2)+b^(2)]

If p be the length of the perpendicular from the origin on the line x/a+y/b=1 , then

If p is the length of the perpendicular from the origin to the line (x)/(a) + (y)/(b) = 1, "then prove that " (1)/(p^(2)) = (1)/(a^(2)) + (1)/(b^(2))

If 2p is the length of perpendicular from the origin to the lines (x)/(a)+(y)/(b)=1, then a^(2),8p^(2),b^(2) are in

The length of perpendicular from the origin on the line x/a + y/b = 1 is -

If 2p is the length of perpendicular from the origin to the lines x/a+ y/b = 1, then a^2,8p^2,b^2 are in

if P is the length of perpendicular from origin to the line (x)/(a)+(y)/(b)=1 then prove that (1)/(a^(2))+(1)/(b^(2))=(1)/(p^(2))

If p is the length of the perpendicular from the origin to the line (x)/(a) + (y)/(b) = 1 , then which of the following is ture ?

I.If p is the length of the perpendicular from the origin on the line (x)/(a)+(y)/(b)=1 and a^(2),p^(2),b^(2) are in A.P,then a^(4)-2p^(2)a^(2)+2p^(4)=