Y is the Young's modulus of the material of a wire of length L and cross-sectional area A. It is stretched through a length l. What is the force constant of the wire?

Young's modules of material of a wire of length ' "L" ' and cross-sectional area "A" is "Y" .If the length of the wire is doubled and cross-sectional area is halved then Young's modules will be :

If Y is the Young's modulus of a wire of cross sectional area A, then the force required to increase its length by 0.1% will be

The product of Young's modulus of the material of the wire with its cross sectional area is equal to its length. Find the parameters representing x and y axes of the curve as shown:

A wire of length L and cross-sectional area A is made of a material of Young's modulus Y. IF the wire is stretched by an amount x, the workdone is

A wire of length L and cross section A is made of material of young's modulus y. It is stretched by an amount x. What is the work done ?

The Youngs modulus of the material of the wire of length L and radius r is Y Nm^(-2) . If the length is reduced to L/2 and radius r/2, then Youngs modulus will be.

A wire of length L and cross-sectional area A is made of material of Young's modulus Y. The work done in stretching the wire by an amount x is

Young's modulus of the material of a wire is Y. ON pulling the wire by a force F, the increase in its length is x. The potential energy of the stretched wire is