A person has to completely put each of three liquids: 403 litres of petrol, 465 litres of diesel and 496 litres of Mobil Oil in bottles of equal size without mixing any of the above three types of liquids such that each bottle is completely filled. What is the least possible number of bottles required? (a) 34       (b) 44     (c) 46    (d) None of these

Mr. Black has three kinds of wine, of the first kind 403 litres, of the second 434 litres of the third 465 litres what is the least number of full casks of equal size in which this can be stored without mixing?

Let's write a story line and then work out - ( c) 52.2 ÷ 5.8 52.2 litres oils is stored in a big jar. Bottles of equal size are to be filled with this oils. If each bottle hold 5.8 litre of oils. Let’s find how many such bottles can be filled.

A,B and C are all liquid ,Liquid A has a comparatively low boiling point on heating liquid A vaporises completely either alone or by mixing with petrol ,Liquid A is being used increasingly as a fuel in motor vehicles either alone or by mixing with petrol liquid B has very high boiling point it also vaporises completely on heating without leaving any residue liquid B is a conductor of electricity and used in making thermometers Liquid C has a moderate boiling point On heating liquid C vaporises leaving behind a white solid D which is used in cooking vegetables the condensation of vapours from C give a liquid E which turns anhydrous CuSO_(4) to blue (a) which liquid could be an element ? name this element . (b) which liquid could be a mixture ? name this mixture . ( c) which liquid could be a compound ? name this compound. ( d) what could the solid D be ? (e ) what do you think is liquid E ?

A density bottle weighs 120 g and 100 g when filled completely with oil ad water, respectively. If the weight of a empty density bottle is 40g, then arrange the following steps in sequence meant to solve the problem to get the density of oil (A). The density of the oil D=("Mass of the oil")/("Weight of the water")=("Mass of the oil")/("Mass of the water") =("Weighht of oil")/("Weight of the water")=(W_(3)-W_(1))/(W_(2)-W_(1)) (B). Let the weight of the bottle +oil= W_(3)=120g and the weight of the bottle+water = W_(2) 100g, where bottle is completely filled with liquid, i.e., oil or water. (C). Let the weight of the empty bottle =W_(1)=40g (D). The the weight of the oil ad water would be equal to (W_(3)-W_(1)) and (W_(2)-W_(1)) , respectively.