The electronic configuration , group number and period number of an element with atomic number 10 is
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Its electronic configuration is ` 1 s^2 | 2s^2 2p^2 2p^6 = ( 2.8 )` this means it contains 2 electrons in K - shell and 8 electrons in L shell Its period number = no . Of shells =2 its group number = No. of valance electrons `+ 10 = 8 +10` =18 [If number of valance electrons is more than 2 group number = number of valence electrons + 10]
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