1.00 kg of `.^(235)U` undergoes fission process. If energy released per event is `200 MeV`, then the total energy released is

In a nuclear reactor, the number of U^(235) nuclei undergoing fissions per second is 4xx10^(20). If the energy releases per fission is 250 MeV, then the total energy released in 10 h is (1 eV= 1.6xx10^(-19)J)

In a nuclear reactor, the number of U^(235) nuclei undergoing fissions per second is 4xx10^(20). If the energy releases per fission is 250 MeV, then the total energy released in 10 h is (1 eV= 1.6xx10^(-19)J)

Calculate the total energy released if 1.0 kg of .^(235)U undergoes fission, taking the disintergration energy per event to be Q=208 MeV (a more accurate value than the estimate given previously).

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

The energy released when one nucleus of ._(92)u^(235) undergoes fission is 188 MeV. The energy released when 100g of undergoes fission is ._(92)u^(235)

The fission properties of ""_(94)^(239)Pu are very similar to those of ""_(92)^(235)U . The average energy released per fission is 180 MeV . How much energy , in MeV, is released if all the atoms in 1kg of pure ""_(94)^(239)Pu undergo fission?