[" If "H_(2)(g)+I_(2)(g)longrightarrow2HI(g);Delta H=12.40," kcal.The heat "],[" of formation of HI is: "]

If H_2(g) +I_2(g) rarr 2HI(g), Delta H=12.40 kcal . The enthalpy of formation of HI is

H_(2) (g) +I_(2) (g) rarr 2HI (g), DeltaH=51.9 kJ . According to this, heat of formation of HI is

For the reaction H_(2)+I_(2)hArr2HI , DeltaH=12.40 kcal . The heat of formation (DeltaH) of HI is

For the reaction H_(2)+I_(2)hArr2NHI , DeltaH=12.40 kcal . The heat of formation (DeltaH) of HI is

H_(2)(g) + I_(2) hArr 2HI(g): Delta H = 12.40 kcal . According to this reaction, heat of formation of HI will be

H_2(g)+I_2(g)rarr2HI(g), triangleH=-12.40 kcals , Heat of formation of HI will be

Reaction, H_(2)(g)+I_(2)(g)to2HI,DeltaH=12.40kcal ltbr. According to this, heat of formation of HI will be: