" (vi) "(cos phi)/(1+sin phi)+(1+sin phi)/(cos phi)=2sec phi

tan phi cos ec phi=sec phi

(3 cos phi+cos 3 phi)/(3 sin phi-sin 3 phi)=

The value of (sec phi(1-sin phi)(sin phi+cos phi) (sec phi+tan phi))/(sin phi(1+tan phi)+cos phi(1+ cot phi)) is equal to :

(1+sin phi+i cos phi)/((1+sin phi-i cos phi)^(n))=cos(n(pi)/(2)-n phi)+i sin(n(pi) /(2)-n phi)

The value of sqrt((cosec phi-cot phi)/(cosec phi +cot phi)) div (sin phi)/(1+cos phi) is equal to:

phi is an acute angle such that tan phi=(2)/(3) then evaluate ((1+tan phi)/(sin phi+cos phi))*((1-cot phi)/(sec phi+csc phi ))

The product of matrices A = [(cos^(2) theta, cos theta sin theta),(cos theta sin theta , sin^(2) theta)] and sin B = [(cos^(2)phi, cos phi sin phi),(cos phi sin phi, sin^(2) phi)] is a null matrix if theta - phi =

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi),(cos phi sin phi,sin^2 phi)]=0

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi), (cos phi sin phi,sin^2 phi)]=0

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi),(cos phi sin phi,sin^2 phi)]=0