Parallel combination of two capacitors, each of value `10muF` is charged by 200 volt d.c. Total energy of the capictor in joules will be :

A series combination of N_(1) capacitors (each of capacity C_(1) ) is charged to potential difference 3V. Another parallel combination of N_(2) capacitors (each of capacity C_(2) ) is charged to potential difference V. The total energy stored in both the combinations is same, The value of C_(1) in terms of C_(2) is

A capacitor of 50 mu F is charged to 10 volts. Its energy in joules is

A capacitor of capacitance 1/3muF is connected to a battery of 300volt and charged. Then the energy stored in capacitor is

If n capacitors are connected in parallel to a V volt source, then total energy of the system is:

Two capacitors each of 1muF capacitance are connected in parallel and are then charged by 200 V. The total energy of their charges is

If n capacitors are connected in parallel to a V volt source then total energy of the system is: