What is the solution set for the equation `x^(4) - 26 x^(2) + 25 = 0 `

Options

A. ` {-5, -1, 1, 5 }`
B. ` {-5, -1}`
C. ` {1,5}`
D. ` {-5, 0, 1,5}`

Answer

A

Explanation

Consider , `x^(4) - 26x^(2) + 25 = 0 `
` rArr x^(4) - 25x^(2) - x^(2) + 25 = 0 `
` =x^(2) (x^(2)-25) - (x^(2)- 25)=0`
`rArr (x^(2) - 25) - (x^(2)-1)=0`
`rArr (x-5) (x+5) (x+1) = 0 `
`rArr x=5, -5,1, -1`
`:. " Solution set for given equation is " {5, -5, -1, 1}`