If one of the roots of the equation `(b-c)x^(2) + b(c-a)x + c( a-b) = 0 ` is 1, what is the second root ?

Options

A. `-(b(c-a))/(a(b-c))`
B. `(b(c-a))/(a(b-c))`
C. `(c(a-b))/(a(b-c))`
D. `(c(a-b))/(a(b-c))`

Answer

C

Explanation

Given equation is
`a(b-c)x^(2) + b(c-a)x + c( a-b) = 0 `
Let `alpha` be the second root.
So `(alpha) (1) = (c(a-b))/(a(b-c))`
Hence, `(alpha) = "second root " = (c(a-b))/(a(b-c))`