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2x^(2) + 3x - alpha - 0 " has roots "-2 ...

`2x^(2) + 3x - alpha - 0 " has roots "-2 and beta " while the equation "x^(2) - 3mx + 2m^(2) = 0 " has both roots positive, where " alpha gt 0 and beta gt 0.`
What is the valueof `alpha`?

A

`1//2`

B

1

C

2

D

4

Text Solution

Verified by Experts

The correct Answer is:
C
`2x^(2) + 3 x - alpha = 0 `
`" Its roots are :" -2 & beta.`
i.e., ` (-3)/2 = beta - 2 rArr beta = 2 - 3/2 = 1/2 rArr beta = 1/2 `
` alpha/2 = 2 beta rArr alpha = 4 xx 1/2 rArr alpha = 2`
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