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2x^(2) + 3x - alpha - 0 " has roots "-2 ...

`2x^(2) + 3x - alpha - 0 " has roots "-2 and beta " while the equation "x^(2) - 3mx + 2m^(2) = 0 " has both roots positive, where " alpha gt 0 and beta gt 0.`
If `omega, omega^(2)` are the cube roots of unity, then `(1+omega) (1+omega^(2))(1+omega^(3)) (1+ omega + omega ^(2))` is equal to

A

-2

B

-1

C

0

D

2

Text Solution

Verified by Experts

The correct Answer is:
C
`(1+omega) ( 1+omega^(2)) (1 + omega^(2)) ( 1+ omega+ omega^(2))`
We know , `(1+ omega + omega^(2))=0`. ltbr. So, `(1+omega)(1+omega^(2)) (1+ omega^(3)) (0)=0`
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