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If the derivative of the function f(x) ...

If the derivative of the function `f(x) ={ax^2+b , x lt -1 and bx^2 +ax+4,x leq -1` is everywhere continuous, then-

A

`a=2,b=3`

B

`a=3,b=2`

C

`a=-2,b=-3`

D

`a=-3,b=-2`

Text Solution

Verified by Experts

The correct Answer is:
A

Derivative of `f(x)={{:(ax^(2)+b,xlt-1),(bx^(2)+ax+a,xge-1):}`
is `f(x)={{:(2ax,xlt-1),(2bx+a,xge-1):}`
If f'(x) is contnuons everywhere then it is also continuous at x=-1
`f'(x)|_(x=-1)=-2a=-2b+a`
or, 3a=2b" "…..(i)
From the given choice a=2,b=3 satisfied this equation.
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