Without using log tables evaluate: `2log_(10)5+log_(10)8-(1)/(2)log_(10)4`

Without using tables, find the value of 4log_(10)5+5log_(10)2-(1)/(2)log_(10)4 .

log_(10)3+log_(10)2-2log_(10)5

Find the value of log_(10)5*log_(10)20+(log_(10)2)^(2)

(1)/(3)log_(10)125-2log_(10)4+log_(10)32

The value of (log_(10)2)^(3)+log_(10)8log_(10)5+(log_(10)5)^(3) is

The value of (1)/(5) log_(10) 3125 -4 log_(10)2 +log_(10)32 is

What is the value of (1/3 log_(10)125 - 2log_(10)4 + log_(10)32 + log_(10)I) ?

Evaluate each of the following without using tables : (i) log 5 + log 8 - 2 log 2 (ii) log_(10) 8 + log_(10) 25 + 2 log_(10)3 - log_(10) 18 (iii) log 4 + (1)/(3) log 125 - (1)/(5) log 32

(log_(10)2)^(3)+log_(10)8*log_(10)5+(log_(10)5)^(3) is

Find domain of the function log_(10)log_(10)log_(10)log_(10)log_(10)x