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If g(x)=(1)/(f(x))andf(x)=x,xne0, then w...

If `g(x)=(1)/(f(x))andf(x)=x,xne0`, then which one of the following is correct

A

`f(f(f(g(g(f(x))))))=g(g(f(g(f(x)))))`

B

`f(f(g(3(g(f(x))))))=g(g(f(g(f(x))))))`

C

`f(g(f(g(g(f(g(x))))))=g(g(f(g(f(x))))))`

D

`f(f(f(f(f(f(x))))))=f(f(f(g(x)))))`

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The correct Answer is:
To solve the problem, we need to analyze the functions given and determine which option is correct based on the relationships between \( f(x) \) and \( g(x) \). ### Step-by-step Solution: 1. **Define the Functions**: We are given: \[ f(x) = x \quad \text{for } x \neq 0 \] and \[ g(x) = \frac{1}{f(x)} \] 2. **Substitute \( f(x) \) into \( g(x) \)**: Since \( f(x) = x \), we can substitute this into \( g(x) \): \[ g(x) = \frac{1}{f(x)} = \frac{1}{x} \quad \text{for } x \neq 0 \] 3. **Calculate \( g(f(x)) \)**: Now, we need to find \( g(f(x)) \): \[ g(f(x)) = g(x) = \frac{1}{x} \] 4. **Calculate \( f(g(x)) \)**: Next, we find \( f(g(x)) \): \[ f(g(x)) = f\left(\frac{1}{x}\right) = \frac{1}{x} \quad \text{for } x \neq 0 \] 5. **Check the Composition \( f(g(x)) \) and \( g(f(x)) \)**: We can see that: \[ g(f(x)) = \frac{1}{x} \quad \text{and} \quad f(g(x)) = \frac{1}{x} \] Thus, we can conclude: \[ f(g(x)) = g(f(x)) \] 6. **Evaluate Options**: We need to evaluate the options given in the question. We will check if the expressions involving \( f \) and \( g \) are equal or not. - **Option A**: \( f(f(f(g(x)))) = g(f(x)) \) - **Option B**: \( g(f(g(x))) = f(g(x)) \) - **Option C**: \( f(g(f(x))) = g(g(x)) \) - **Option D**: \( g(g(f(x))) = f(f(x)) \) We will check each option based on our derived results. - **Option A**: \[ f(f(f(g(x)))) = f(f(f(\frac{1}{x}))) = f(f(\frac{1}{x})) = f(\frac{1}{x}) = \frac{1}{x} \] And, \[ g(f(x)) = \frac{1}{x} \] So, **Option A is correct**. - **Option B**: \[ g(f(g(x))) = g(f(\frac{1}{x})) = g(\frac{1}{x}) = x \] And, \[ f(g(x)) = \frac{1}{x} \] So, **Option B is incorrect**. - **Option C**: \[ f(g(f(x))) = f(g(x)) = f(\frac{1}{x}) = \frac{1}{x} \] And, \[ g(g(x)) = g(\frac{1}{x}) = x \] So, **Option C is incorrect**. - **Option D**: \[ g(g(f(x))) = g(g(x)) = g(\frac{1}{x}) = x \] And, \[ f(f(x)) = f(x) = x \] So, **Option D is incorrect**. ### Conclusion: From the analysis, we find that **Option A is correct**.

To solve the problem, we need to analyze the functions given and determine which option is correct based on the relationships between \( f(x) \) and \( g(x) \). ### Step-by-step Solution: 1. **Define the Functions**: We are given: \[ f(x) = x \quad \text{for } x \neq 0 ...
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NDA PREVIOUS YEARS-FUNCTIONS, LIMIT, CONTINUITY AND DIFFERENTIABILITY-MCQs
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  2. Consider the function f(x)={{:((alphacosx)/(pi-2x),If,xne(pi)/(2)),(...

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  3. If g(x)=(1)/(f(x))andf(x)=x,xne0, then which one of the following is c...

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  4. If f(x)=sqet(25-x^(2)), then what is Lim(x to 1) (f(x)-f(1))/(x-1) equ...

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  5. Consider the function f(x)={{:(ax-2,"for",-2ltxlt-1),(-1,"for",-1lex...

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  6. The function f(x)=(1-sinx+cosx)/(1+sinx+cosx) is not defined at x=pi. ...

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  7. Consider the following functions: 1. f(x)={{:((1)/(x),if,xne0),(0,if...

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  9. Consider the following statements : 1. The function f(x)=x^(2)+2cosx...

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  10. If f:IRtoIRtoIR be two functions given by f(x)=2x-3andg(x)=x^(3)+5" th...

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  11. If f(x)=(sin(e^(x-2)-1))/(1n(x-1)), then lim(xto2)f(x) is equal to

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  12. Consider the following statements : Statement 1 : The function f:IRt...

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  13. Consider the function f(x)={{:(-2sinx,if,xle-(pi)/(2)),(Asinx+B,if,-...

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  14. Consider the function f(x)={{:(-2sinx,if,xle-(pi)/(2)),(Asinx+B,if,-...

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  15. Consider the curves f(x)=x|x|-1andg(x)={{:((3x)/(2)","xgt0),(2x","xl...

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  16. Consider the curves f(x)=x|x|-1andg(x)={{:((3x)/(2)","xgt0),(2x","xl...

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  18. Cosider the function f(x)=|x-1|+x^(2)" where " x""inR. which one of ...

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  19. Which one the following statements is correct?

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