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The domain of the function f(x)=(1)/(sqr...

The domain of the function `f(x)=(1)/(sqrt|x|-x)` is

A

`[0,oo)`

B

`(-oo,0)`

C

`[1,oo)`

D

`(-oo,0]`

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The correct Answer is:
To find the domain of the function \( f(x) = \frac{1}{\sqrt{|x| - x}} \), we need to ensure that the expression inside the square root is positive and that the denominator is not equal to zero. Let's go through the steps to determine the domain. ### Step 1: Identify the expression under the square root The expression we need to analyze is \( |x| - x \). ### Step 2: Analyze the cases for \( |x| \) The absolute value function \( |x| \) behaves differently based on whether \( x \) is positive or negative: - If \( x \geq 0 \), then \( |x| = x \). - If \( x < 0 \), then \( |x| = -x \). ### Step 3: Case 1 - When \( x \geq 0 \) If \( x \geq 0 \): \[ |x| - x = x - x = 0 \] In this case, the expression under the square root becomes zero, which means the function is undefined (since we cannot divide by zero). Therefore, \( x \geq 0 \) is not in the domain. ### Step 4: Case 2 - When \( x < 0 \) If \( x < 0 \): \[ |x| - x = -x - x = -2x \] For the square root to be defined and positive: \[ -2x > 0 \implies x < 0 \] This condition is satisfied for all \( x < 0 \). ### Step 5: Conclusion Since the function is undefined for \( x \geq 0 \) and valid for \( x < 0 \), the domain of the function is: \[ (-\infty, 0) \] ### Final Answer The domain of the function \( f(x) = \frac{1}{\sqrt{|x| - x}} \) is \( (-\infty, 0) \). ---

To find the domain of the function \( f(x) = \frac{1}{\sqrt{|x| - x}} \), we need to ensure that the expression inside the square root is positive and that the denominator is not equal to zero. Let's go through the steps to determine the domain. ### Step 1: Identify the expression under the square root The expression we need to analyze is \( |x| - x \). ### Step 2: Analyze the cases for \( |x| \) The absolute value function \( |x| \) behaves differently based on whether \( x \) is positive or negative: - If \( x \geq 0 \), then \( |x| = x \). ...
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