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If f(x)=sqrt(x-1)/(x-4) defines a functi...

If `f(x)=sqrt(x-1)/(x-4)` defines a function of R, then what is its domain?

A

`(-oo,4)uu(4,oo)`

B

`[4,oo]`

C

`(1,4)uu(4,oo)`

D

`[1,4)uu(4,oo)`

Text Solution

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The correct Answer is:
To find the domain of the function \( f(x) = \frac{\sqrt{x-1}}{x-4} \), we need to determine the values of \( x \) for which the function is defined. ### Step-by-Step Solution: 1. **Identify the Square Root Condition**: The expression under the square root, \( x - 1 \), must be non-negative for the square root to be defined. Therefore, we set up the inequality: \[ x - 1 \geq 0 \] Solving this gives: \[ x \geq 1 \] 2. **Identify the Denominator Condition**: The denominator \( x - 4 \) cannot be zero, as division by zero is undefined. Therefore, we set up the equation: \[ x - 4 \neq 0 \] Solving this gives: \[ x \neq 4 \] 3. **Combine the Conditions**: From the first condition, we have \( x \geq 1 \). From the second condition, we have \( x \neq 4 \). Thus, the values of \( x \) that satisfy both conditions are: \[ x \in [1, 4) \cup (4, \infty) \] ### Conclusion: The domain of the function \( f(x) = \frac{\sqrt{x-1}}{x-4} \) is: \[ \text{Domain} = [1, 4) \cup (4, \infty) \]

To find the domain of the function \( f(x) = \frac{\sqrt{x-1}}{x-4} \), we need to determine the values of \( x \) for which the function is defined. ### Step-by-Step Solution: 1. **Identify the Square Root Condition**: The expression under the square root, \( x - 1 \), must be non-negative for the square root to be defined. Therefore, we set up the inequality: \[ x - 1 \geq 0 ...
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