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The arithmetic mean of ""^(n)C(0),""^(n)...

The arithmetic mean of `""^(n)C_(0),""^(n)C_(1),""^(n)C_(2), ..., ""^(n)C_(n)`, is

A

`(2^(n)-1)//n`

B

`2^(n)//(n+1)`

C

`(2^(n))//n`

D

`2^((n+1))//(n+1)`

Text Solution

Verified by Experts

The correct Answer is:
A
Arithmetic mean of the series
`=(.^(n)C_(1)+.^(n)C_(2)+.^(n)C_(3)+...+.^(n)C_(n))/(n)=(2^(n)-1)/(n)`
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