The regression coefficients of a bivariate distribution are `-0.64 and -.36`. Then the correlation coefficient of the distribution is

Options

A. `0.48`
B. `-0.48`
C. `0.50`
D. `-0.50`

Answer

B

Explanation

Let `b_(1)=-0.64`
`b_(2)=-0.36`
`r=pm sqrt(-0.64xx-0.36)=pm0.48`
`because b_(1)lt0 & b_(2)lt0`
`therefore r=-0.48`
`rArr r=-0.48`