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If the three observations are 3, -6 and ...

If the three observations are 3, -6 and -6, then what is their harmonic mean?

A

0

B

`oo`

C

`-1//2`

D

`-3`

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The correct Answer is:
To find the harmonic mean (HM) of the three observations 3, -6, and -6, we can use the formula for the harmonic mean of three numbers, which is given by: \[ HM = \frac{3}{\frac{1}{x_1} + \frac{1}{x_2} + \frac{1}{x_3}} \] ### Step 1: Identify the values Let \( x_1 = 3 \), \( x_2 = -6 \), and \( x_3 = -6 \). ### Step 2: Calculate the reciprocals Now, we need to calculate the reciprocals of these values: \[ \frac{1}{x_1} = \frac{1}{3}, \quad \frac{1}{x_2} = \frac{1}{-6}, \quad \frac{1}{x_3} = \frac{1}{-6} \] ### Step 3: Sum the reciprocals Next, we sum these reciprocals: \[ \frac{1}{x_1} + \frac{1}{x_2} + \frac{1}{x_3} = \frac{1}{3} + \left(-\frac{1}{6}\right) + \left(-\frac{1}{6}\right) \] \[ = \frac{1}{3} - \frac{1}{6} - \frac{1}{6} \] ### Step 4: Find a common denominator To combine these fractions, we find a common denominator, which is 6: \[ \frac{1}{3} = \frac{2}{6} \] Thus, \[ \frac{1}{3} - \frac{1}{6} - \frac{1}{6} = \frac{2}{6} - \frac{1}{6} - \frac{1}{6} = \frac{2 - 1 - 1}{6} = \frac{0}{6} = 0 \] ### Step 5: Substitute back into the HM formula Now we substitute this sum back into the harmonic mean formula: \[ HM = \frac{3}{\frac{1}{3} + \frac{1}{-6} + \frac{1}{-6}} = \frac{3}{0} \] ### Step 6: Conclusion Since division by zero is undefined, the harmonic mean of the three observations 3, -6, and -6 is undefined.

To find the harmonic mean (HM) of the three observations 3, -6, and -6, we can use the formula for the harmonic mean of three numbers, which is given by: \[ HM = \frac{3}{\frac{1}{x_1} + \frac{1}{x_2} + \frac{1}{x_3}} \] ### Step 1: Identify the values Let \( x_1 = 3 \), \( x_2 = -6 \), and \( x_3 = -6 \). ...
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