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If the AM and GM between two number are in the ratio m : n, then what is the ratio between the two numbers?

A

`(m+sqrt(m^(2)-n^(2)))/(m-sqrt(m^(2)-n^(2)))`

B

`(m+n)/(m-n)`

C

`(m^(2)-n^(2))/(m^(2)+n^(2))`

D

`(m^(2)+n^(2)-nm)/(m^(2)+n^(2)+mn)`

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AI Generated Solution

The correct Answer is:
To find the ratio between two numbers \( a \) and \( b \) given that their Arithmetic Mean (AM) and Geometric Mean (GM) are in the ratio \( m:n \), we can follow these steps: ### Step 1: Define AM and GM The Arithmetic Mean (AM) of two numbers \( a \) and \( b \) is given by: \[ AM = \frac{a + b}{2} \] The Geometric Mean (GM) of \( a \) and \( b \) is given by: \[ GM = \sqrt{ab} \] ### Step 2: Set up the ratio According to the problem, the ratio of AM to GM is given as: \[ \frac{AM}{GM} = \frac{m}{n} \] Substituting the expressions for AM and GM, we have: \[ \frac{\frac{a + b}{2}}{\sqrt{ab}} = \frac{m}{n} \] ### Step 3: Cross-multiply to eliminate the fraction Cross-multiplying gives: \[ n(a + b) = 2m\sqrt{ab} \] ### Step 4: Square both sides to eliminate the square root Squaring both sides results in: \[ n^2(a + b)^2 = 4m^2ab \] ### Step 5: Expand the left-hand side Expanding the left-hand side: \[ n^2(a^2 + 2ab + b^2) = 4m^2ab \] ### Step 6: Rearranging the equation Rearranging gives: \[ n^2a^2 + 2n^2ab + n^2b^2 - 4m^2ab = 0 \] This simplifies to: \[ n^2a^2 + (2n^2 - 4m^2)ab + n^2b^2 = 0 \] ### Step 7: Treat as a quadratic in \( a \) This is a quadratic equation in terms of \( a \): \[ n^2a^2 + (2n^2 - 4m^2)ab + n^2b^2 = 0 \] ### Step 8: Use the quadratic formula Using the quadratic formula \( a = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A} \), where: - \( A = n^2 \) - \( B = (2n^2 - 4m^2)b \) - \( C = n^2b^2 \) The discriminant \( D \) is: \[ D = (2n^2 - 4m^2)^2b^2 - 4n^2(n^2b^2) \] ### Step 9: Find the ratio \( \frac{a}{b} \) From the quadratic formula, we can derive the ratio \( \frac{a}{b} \): \[ \frac{a}{b} = \frac{m + \sqrt{m^2 - n^2}}{m - \sqrt{m^2 - n^2}} \] ### Conclusion Thus, the ratio of the two numbers \( a \) and \( b \) is: \[ \frac{a}{b} = \frac{m + \sqrt{m^2 - n^2}}{m - \sqrt{m^2 - n^2}} \]

To find the ratio between two numbers \( a \) and \( b \) given that their Arithmetic Mean (AM) and Geometric Mean (GM) are in the ratio \( m:n \), we can follow these steps: ### Step 1: Define AM and GM The Arithmetic Mean (AM) of two numbers \( a \) and \( b \) is given by: \[ AM = \frac{a + b}{2} \] The Geometric Mean (GM) of \( a \) and \( b \) is given by: ...
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