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What is the geometric mean of the sequen...

What is the geometric mean of the sequence `1,2, 4, 8,..., 2^n`

A

`2^(n//2`

B

`2^((n+1)//2)`

C

`2^((n+1))-1`

D

`2^((n-1))`

Text Solution

Verified by Experts

The correct Answer is:
A

Geometric mean `=root(n+1)(1.2.4.8...2^(2))`
`(because" there are "(n+1)" multiples from "2^(@)" to "2^(n))`
`=root(n+1)(2^(0).2^(1).2^(2).2^(3)...2^(n))`
`=root(n+1)(2^(1+2+3+...n))=root(n+1)(2^((n(n+1))/(2)))`
`=[2^((n(n+1))/(2))]^((1)/(n+1))=2^((n)/(2))`
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