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If omega denotes the cube root of unity,...

If `omega` denotes the cube root of unity, then what is the real root of the equaton `x^(3)-27=0` ?

A

`3 omega`

B

`3omega^(2)`

C

`-3omega`

D

`3omega^(3)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the equation \( x^3 - 27 = 0 \) and find the real root, we can follow these steps: ### Step 1: Set the equation to zero We start with the equation: \[ x^3 - 27 = 0 \] ### Step 2: Isolate \( x^3 \) To isolate \( x^3 \), we add 27 to both sides: \[ x^3 = 27 \] ### Step 3: Take the cube root Next, we take the cube root of both sides to solve for \( x \): \[ x = \sqrt[3]{27} \] ### Step 4: Calculate the cube root We know that \( 27 = 3^3 \), so: \[ x = \sqrt[3]{3^3} = 3 \] ### Conclusion The real root of the equation \( x^3 - 27 = 0 \) is: \[ \boxed{3} \]

To solve the equation \( x^3 - 27 = 0 \) and find the real root, we can follow these steps: ### Step 1: Set the equation to zero We start with the equation: \[ x^3 - 27 = 0 \] ...
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