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If |z+barz|=|z-barz| then locus of z is...

If `|z+barz|=|z-barz|` then locus of z is

A

A pair of straight lines

B

A line

C

A set of four straight lines

D

A circle

Text Solution

Verified by Experts

The correct Answer is:
A
Let `z=x+iy, barz=x-iy`
`|z+barz|=|z-barz|`
`|(x+iy)+(x-iy)|=|(x+iy)-(x-iy)|`
`x=+-y`
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