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A complex number is given by z=(1+2i)/(...

A complex number is given by `z=(1+2i)/(1-(1-i)^(2))`
What is the principal argument of z?

A

0

B

`(pi)/(4)`

C

`(pi)/(2)`

D

`pi`

Text Solution

Verified by Experts

The correct Answer is:
A
`z=(1+2i)/(1-(1-i)^(2))=1=+0.i`
`therefore"Principal argument of"z=tantheta`
`=0/1=0`
`thereforetheta=0^(@)`
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