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The general solution fo (dy)/(dx) = (ax ...

The general solution fo `(dy)/(dx) = (ax +h)/(by +h) ` represents a circle only when

A

a=b=0

B

` a= -b ne 0`

C

` a= bne 0, h =k`

D

` a = bne 0`

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The correct Answer is:
B

`(dy)/(dx)= (ax +h)/(by +k)`
` Rightarrow (by+ k) dy = (ax +h) dx`
Intergrating,we get ` int (by + k) dy = int (ax+h) dx`
` Rightarrow (by^(2))/2 + ky = (ax^(2))/2 + hx`
` Rightarrow ax^(2) -by^(2) =ax^(2) -2ky =0`
This repesents circle only when ` a = -b ne 0` .
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