A wire 34cm long is to be bent in the form of a quadrialteral of which each angle is `90^(@)` what is the maximum area which can be enclosed inside the quadrialteral

Options

A. 68 `cm^(2)`
B. `70 cm^(2)`
C. `71.25 cm^(2)`
D. `72.25 cm^(2)`

Answer

D

Explanation

Let on side of quadrilateral be x and another side be y so 2(x+y)=34
or (x+y)=17
We know from the basic principal that for a given perimeter squre has the maximum area so x =y and putting this value in equation (i)
`x=y=17/2`
Area `=x.y=17/2xx17/2=289/4=72.25`