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What is the slope of the tangent to the ...

What is the slope of the tangent to the curve `y=sin^(1)(sin^(2)x)`

A

0

B

1

C

2

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`y=sin^(-1) (sin ^(2)y)`
`(dy)/(dx)=(2sin x cos x)/sqrt(1-sin^(4)x) rarr (dy)/(dx)=(sin 2x)/sqrt(1-sin^(4)x)`
at x=0 , `(dy)/(dx)=0`
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