Home
Class 12
MATHS
A cylinder is inscribed in a sphere of r...

A cylinder is inscribed in a sphere of radius r
What is the radius of the cylinder of maximum volume ?

A

`(2r)/sqrt(3)`

B

`sqrt(2)/(sqrt(3)``r`

C

r

D

`sqrt(3r)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the radius of the cylinder of maximum volume inscribed in a sphere of radius \( r \), we can follow these steps: ### Step 1: Understand the Geometry We have a cylinder inscribed in a sphere. The radius of the sphere is \( r \), and we denote the radius of the cylinder as \( R \) and its height as \( h \). ### Step 2: Relate the Cylinder and Sphere Using the geometry of the situation, we can apply the Pythagorean theorem. The relationship can be expressed as: \[ R^2 + \left(\frac{h}{2}\right)^2 = r^2 \] This equation arises because the radius of the sphere is the hypotenuse of a right triangle formed by the radius of the cylinder and half the height of the cylinder. ### Step 3: Express Height in Terms of Radius From the Pythagorean theorem, we can express \( h \) in terms of \( R \): \[ h = 2\sqrt{r^2 - R^2} \] ### Step 4: Write the Volume of the Cylinder The volume \( V \) of the cylinder is given by: \[ V = \pi R^2 h \] Substituting \( h \) from the previous step: \[ V = \pi R^2 \cdot 2\sqrt{r^2 - R^2} = 2\pi R^2 \sqrt{r^2 - R^2} \] ### Step 5: Differentiate to Find Maximum Volume To find the maximum volume, we need to differentiate \( V \) with respect to \( R \) and set the derivative equal to zero: \[ \frac{dV}{dR} = 2\pi \left( 2R \sqrt{r^2 - R^2} + R^2 \cdot \frac{-R}{\sqrt{r^2 - R^2}} \right) = 0 \] This simplifies to: \[ 2R \sqrt{r^2 - R^2} - \frac{R^3}{\sqrt{r^2 - R^2}} = 0 \] Multiplying through by \( \sqrt{r^2 - R^2} \): \[ 2R(r^2 - R^2) - R^3 = 0 \] \[ 2Rr^2 - 3R^3 = 0 \] Factoring out \( R \): \[ R(2r^2 - 3R^2) = 0 \] Thus, we have two cases: \( R = 0 \) or \( 2r^2 - 3R^2 = 0 \). ### Step 6: Solve for \( R \) From \( 2r^2 - 3R^2 = 0 \): \[ 3R^2 = 2r^2 \implies R^2 = \frac{2r^2}{3} \implies R = \sqrt{\frac{2}{3}} r \] ### Conclusion The radius of the cylinder of maximum volume inscribed in a sphere of radius \( r \) is: \[ R = \frac{r\sqrt{2}}{\sqrt{3}} \]

To find the radius of the cylinder of maximum volume inscribed in a sphere of radius \( r \), we can follow these steps: ### Step 1: Understand the Geometry We have a cylinder inscribed in a sphere. The radius of the sphere is \( r \), and we denote the radius of the cylinder as \( R \) and its height as \( h \). ### Step 2: Relate the Cylinder and Sphere Using the geometry of the situation, we can apply the Pythagorean theorem. The relationship can be expressed as: \[ ...
Promotional Banner

Topper's Solved these Questions

  • 3-D GEOMETRY

    NDA PREVIOUS YEARS|Exercise MCQ|147 Videos
  • BINOMIAL THEROREM, MATHEMATICAL INDUCTION

    NDA PREVIOUS YEARS|Exercise MQS|65 Videos

Similar Questions

Explore conceptually related problems

A cylinder is inscribed in a sphere of radius R . The volume V of the cylinder is written as v=f(x), wherex is the height of the cylinder

A right circular cylinder is inscribed in a cone. show that the curved surface area of the cylinder is maximum when the diameter of the cylinder is equal to the radius of the base of the cone.

Show that the altitude of the right circulau cone of maximum volume that can be inscribed in a sphere of radius r is (4r) /(3) . also show that the maximum volume of cone is (8)/(27) of the volume of the sphere.

A cylinder of height 2x is circumscribed by a sphere of radius 2x such that the circular ends of the cylinder are two small circles on the sphere. What is the ratio of the curved surface area of the cylinder to the surface area of the sphere?

Show that the height of the cylinder of maximum volume that can be inscribed in a sphere of radius R is 2(R)/(sqrt(3)) .Also find maximum volume.

Show that the height of the cylinder of maximum volume that can be inscribed in a sphere of radius R is (2R)/(sqrt(3)) Also find the maximum volume.

If sum of radius and height of a cylinder is 6, then ist maximum volume is

Show that the altitude of the right circular cone of maximum volume that can be inscribed in a sphere of radius r is (4R)/(3) .Also find maximum volume in terms of volume of the sphere.

NDA PREVIOUS YEARS-APPLICATION OF DERIVATIVES -Example
  1. A rectangular box is to be made form a sheet of 24 inch length and 9 ...

    Text Solution

    |

  2. Show that the height of the cylinder of maximum volume that can be ...

    Text Solution

    |

  3. A cylinder is inscribed in a sphere of radius r What is the radius o...

    Text Solution

    |

  4. Consider the following statements 1. y=(e^(x)+e^(-x))/(2) is an incr...

    Text Solution

    |

  5. Consider the function f(X)=(x^(2)-1)/(x^(2)+1) where x in R At what ...

    Text Solution

    |

  6. What is the minimum value of f(X)?

    Text Solution

    |

  7. Consider the function f(x)=0.75x^(4)-x^(3)-9x^(2)+7 What is the max...

    Text Solution

    |

  8. Consider the following value of the function ? 1 The functin attains...

    Text Solution

    |

  9. Consider the parametric equation

    Text Solution

    |

  10. What is (dy)/(dx) equal to ?

    Text Solution

    |

  11. What is (d^(2)y)/(dx^(2)) equal to ?

    Text Solution

    |

  12. The function f(x)=(x^(2))/(e^(x)) monotonically increasing if

    Text Solution

    |

  13. Consider the following statements 1 f(x)=In x is an increasing funci...

    Text Solution

    |

  14. Consider the fucntion f(x)=((1)/(x))^(2x^2) , where xgt0. At what v...

    Text Solution

    |

  15. The maximum value of the function is

    Text Solution

    |

  16. Consider f(x)=(x^(2))/(2)-kx +1 such that f(0) =0 and f(3)=15 The va...

    Text Solution

    |

  17. f''(-2/3) is equal to

    Text Solution

    |

  18. Separate the intervals of monotonocity for the function f(x)=-2x^3-9x^...

    Text Solution

    |

  19. The function f(x) is a decreasing funciton in the interval

    Text Solution

    |

  20. Consider the function f(theta)=4(sin^(2) theta + cos^(4) theta) what...

    Text Solution

    |