यदि `x = a (cos theta + "log tan" (theta)/(2)), y = a sin theta` तो dx/dy =

If x = a(cos theta + log tan(theta/2)), y = a sin theta find dy/dx at theta = pi/3

If x = a (cos theta + log tan(theta/2)) and y = a sin theta , find the value of (d^2y)/(dx^2) at theta = pi/4

If x = a{costheta + log tan((theta)/(2))} andy = a sin theta, then (dy)/(dx) is equal to

If x=a(cos theta+log tan((theta)/(2))) and y=a sin theta then find (dy)/(dx) at theta=(pi)/(3) and theta=(pi)/(4)

If x = a (cos x + log tan theta/2) and y = a sin theta then dy/dx is equal to

If x=a(cos theta+log(tan((theta)/(2))) and y=a sin theta then find the value of (d^(2)y)/(dx^(2)) at theta=(pi)/(4)

Find dy/dx when x = a (cos theta + theta sin theta) , y = a (sin theta - theta cos theta).