`144y^(2)+24y+1`के गुणनखंड है

बहुपद के गुणनखंड

y^2+24y+144

Position of the point (3,4) with respect to hyperbola x^(2) - 4y^(2) + 24y - 37 = 0 is ………..

The number of factors of 3600 is: 3600 के कितने गुणनखंड है:

The equation of the hyperbola whose foci are (0, pm 13) and length of conjugate axis is 24 is (i) 144y^(2) - 25 x^(2) = 3600 (ii) 144 x^(2) - 25 y^(2) = 3600 (iii) 25x^(2)- 144 y^(2) = 3600 (iv) 25y^(2)-144x^(2)=3600

If (x^(2))/(144)-(y^(2))/(25)=1 . Find the range of (144)/(x)+(25)/(y) .

If (x^(2))/(144)-(y^(2))/(25)=1 . Find the range of (144)/(x)+(25)/(y) .

If (x^(2))/(144)-(y^(2))/(25)=1 . Find the range of (144)/(x)+(25)/(y) .

If x- 4y = 0 and x+ 2y = 24, then what is the value of (2x + 3y) /(2x-3y)? यदि x- 4y = 0 तथा x+ 2y = 24 है, तो (2x + 3y) /(2x-3y) का मान क्या है? ,