Home
Class 14
MATHS
6389-1212-2828=?...

6389-1212-2828=?

A

2349

B

2493

C

2934

D

2394

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \( 6389 - 1212 - 2828 \), we can follow these steps: ### Step 1: Subtract the first two numbers We start by subtracting \( 1212 \) from \( 6389 \). \[ 6389 - 1212 = 5177 \] ### Step 2: Subtract the result from the third number Now, we take the result from Step 1 and subtract \( 2828 \) from it. \[ 5177 - 2828 = 3349 \] ### Final Answer Thus, the value of \( 6389 - 1212 - 2828 \) is \( 3349 \). ---

To solve the expression \( 6389 - 1212 - 2828 \), we can follow these steps: ### Step 1: Subtract the first two numbers We start by subtracting \( 1212 \) from \( 6389 \). \[ 6389 - 1212 = 5177 \] ...
Promotional Banner

Topper's Solved these Questions

  • SIMPLE INTEREST AND COMPOUND INTEREST

    IBPS & SBI PREVIOUS YEAR PAPER|Exercise MCQs|78 Videos
  • TIME , SPEED & DISTANCE (BOAT & STREAM)

    IBPS & SBI PREVIOUS YEAR PAPER|Exercise Question|91 Videos

Similar Questions

Explore conceptually related problems

8282 + 2828 = ? xx 40

Calculate mean deviation from the median of the following data: Class interval: 0-66-1212-1818-2424-30 Frequency 45362

Find the mean deviation about the median of the following frequency distribution: Class: 0 - 6,6-12,12-18,18-24,24-30 Frequency: 8,10,12,9,5

A company markets a particular brand of electrical fans.The life of fans (in months) is give the following distribution.Determine the modal class and median class.Age(in months) 0-66-1212-1818-2424-3030-3636-4242-48 No.of fans 6.1520252540321820

Consider the following frequency distribution : {:("Class :",0-6,6-12,12-18,18-24,24-30),("Frequency : ",a,b,12,9,5):} If mean = (309)/(22) and median = 14, then the value (a-b)^(2) is equal to __________ .

For the following grouped frequency distribution find the mode: Class: 3-6,6-9,9-12,12-15,15-18,18-21,21-24 Frequency: 25,10,23,12,3

= 6 andand tancThe value of tan7equal to3-23-212+12+1(2)(2) 13 - 1212-1FB) and13 +52(3) Tom13 +52(4)12-1b is equal

The time required for some students to complete a science experiment and the number of students is shown in the following grouped frequency distribution table. Draw the frequency polygon with the help of histogram using given information : {:("Time required for experiment ( minutes)",20-22,22-24,24-26,26-28,28-30,30-32),("Number of students",6,14,20,16,12,10):}

1.1 + 12.12 + 123.123 = ? A. 134.343 B. 133.433 C. 132.123 D.136.343

Calculate the mean deviation about the mean for the following frequency distribution Class interval 0-4,4-8,8-12,12-16,16-20 Frequency 4,6,8,5,2